Experiment Name:
Dyeing of 100% polyester woven fabric with Disperse dye(Carrier Method).
Theory: The term “disperse dye” have been applied to
the organic colouring substances which are free from ionizing groups, are of
low water solubility and are suitable for dyeing hydrophobic fibres. Disperse
dyes have substantivity for one or more hydrophobic fibres e.g. cellulose
acetate, nylon, polyester, acrylic and other synthetic fibres. The negative
charge on the surface of hydrophobic fibres like polyester cannot be reduced by
any means, so non-ionic dyes like disperse dyes are used which are not
influenced by that surface charge.
Objective:
1.
To learn about dyeing process of polyester
fabric by disperse dye.
2.
To dye polyester fabric by disperse dye.
Nature of sample:
Pre-treated 100%
polyester woven fabric.
Apparatus required:
1.Beakers
2.Glass Rod.
3.Pipette.
4. Measuring Cylinder.
5. Digital Balance.
6. Tri-pod stand.
7. Gas Burner.
8. Thermometer.
9. Pot.
Process Sequence:
- Collection of sample
- Set water level
- Add Acetic acid solution
- check pH
- Add carrier solution
- Add dispersing agent solution
- Add disperse dye solution
- Add fabric sample
- Raise temperature to 90deg C
- Run time for 20 minutes
- Bath Drop
- Rinsing
Table1: Dyeing Recipe
SL
|
Process Parameter
|
Unit
|
Dossing
|
Stock soln:
|
01
|
Disperse Dye
|
%
|
1
|
1%
|
02
|
Carrier
|
g/L
|
2
|
1%
|
03
|
Dispersing Agent
|
g/L
|
1
|
1%
|
04
|
Aceic Acid
|
ml
|
0.5
|
-
|
05
|
M : L
|
---
|
1:30
|
-
|
06
|
Fabric Weight
|
gm
|
5
|
-
|
07
|
Temperature
|
deg C
|
100
|
-
|
08
|
Time
|
Min
|
20
|
-
|
Calculation:
Total Liquor = Fabric weight X L [M:L = 01:30]
=
5 X 30
=
150mL
Dye 1% = (Fabric
weight X x%) / stock solution%
= (5X1%)
/ 1%
=5mL
Carrier = (Total liquor X 'x'g/L) / (stock solution% X 1000)
=
(150 X 2) / 1% X 1000
=
30ml
Dispersing Agent = (Total liquor X 'x'g/L) / (stock
solution% X 1000)
=
(150 X 1) / 1% X 1000
=
15mL
Acetic Acid : 0.5ml
Initial Water = total liquor - (chemical 1 + chemical 2 +
chemical 3 ...)
= 150-
(5+30+15+0.5) mL
= 150
-50.5 mL
=
99.5mL
Process Curve:
Sample Attachment & Observation: >>>>
Conclusion: >>>>>>>>>>